Optimal. Leaf size=144 \[ -\frac {c^{3/2} (-5 B+i A) \tanh ^{-1}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right )}{\sqrt {2} a f}+\frac {c (-5 B+i A) \sqrt {c-i c \tan (e+f x)}}{2 a f}+\frac {(-B+i A) (c-i c \tan (e+f x))^{3/2}}{2 a f (1+i \tan (e+f x))} \]
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Rubi [A] time = 0.22, antiderivative size = 144, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 43, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.116, Rules used = {3588, 78, 50, 63, 208} \[ -\frac {c^{3/2} (-5 B+i A) \tanh ^{-1}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right )}{\sqrt {2} a f}+\frac {c (-5 B+i A) \sqrt {c-i c \tan (e+f x)}}{2 a f}+\frac {(-B+i A) (c-i c \tan (e+f x))^{3/2}}{2 a f (1+i \tan (e+f x))} \]
Antiderivative was successfully verified.
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Rule 50
Rule 63
Rule 78
Rule 208
Rule 3588
Rubi steps
\begin {align*} \int \frac {(A+B \tan (e+f x)) (c-i c \tan (e+f x))^{3/2}}{a+i a \tan (e+f x)} \, dx &=\frac {(a c) \operatorname {Subst}\left (\int \frac {(A+B x) \sqrt {c-i c x}}{(a+i a x)^2} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac {(i A-B) (c-i c \tan (e+f x))^{3/2}}{2 a f (1+i \tan (e+f x))}-\frac {((A+5 i B) c) \operatorname {Subst}\left (\int \frac {\sqrt {c-i c x}}{a+i a x} \, dx,x,\tan (e+f x)\right )}{4 f}\\ &=\frac {(i A-5 B) c \sqrt {c-i c \tan (e+f x)}}{2 a f}+\frac {(i A-B) (c-i c \tan (e+f x))^{3/2}}{2 a f (1+i \tan (e+f x))}-\frac {\left ((A+5 i B) c^2\right ) \operatorname {Subst}\left (\int \frac {1}{(a+i a x) \sqrt {c-i c x}} \, dx,x,\tan (e+f x)\right )}{2 f}\\ &=\frac {(i A-5 B) c \sqrt {c-i c \tan (e+f x)}}{2 a f}+\frac {(i A-B) (c-i c \tan (e+f x))^{3/2}}{2 a f (1+i \tan (e+f x))}-\frac {((i A-5 B) c) \operatorname {Subst}\left (\int \frac {1}{2 a-\frac {a x^2}{c}} \, dx,x,\sqrt {c-i c \tan (e+f x)}\right )}{f}\\ &=-\frac {(i A-5 B) c^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right )}{\sqrt {2} a f}+\frac {(i A-5 B) c \sqrt {c-i c \tan (e+f x)}}{2 a f}+\frac {(i A-B) (c-i c \tan (e+f x))^{3/2}}{2 a f (1+i \tan (e+f x))}\\ \end {align*}
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Mathematica [F] time = 180.00, size = 0, normalized size = 0.00 \[ \text {\$Aborted} \]
Verification is Not applicable to the result.
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fricas [B] time = 0.61, size = 337, normalized size = 2.34 \[ \frac {{\left (a f \sqrt {-\frac {{\left (2 \, A^{2} + 20 i \, A B - 50 \, B^{2}\right )} c^{3}}{a^{2} f^{2}}} e^{\left (2 i \, f x + 2 i \, e\right )} \log \left (\frac {{\left ({\left (-2 i \, A + 10 \, B\right )} c^{2} + \sqrt {2} {\left (a f e^{\left (2 i \, f x + 2 i \, e\right )} + a f\right )} \sqrt {-\frac {{\left (2 \, A^{2} + 20 i \, A B - 50 \, B^{2}\right )} c^{3}}{a^{2} f^{2}}} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-i \, f x - i \, e\right )}}{a f}\right ) - a f \sqrt {-\frac {{\left (2 \, A^{2} + 20 i \, A B - 50 \, B^{2}\right )} c^{3}}{a^{2} f^{2}}} e^{\left (2 i \, f x + 2 i \, e\right )} \log \left (\frac {{\left ({\left (-2 i \, A + 10 \, B\right )} c^{2} - \sqrt {2} {\left (a f e^{\left (2 i \, f x + 2 i \, e\right )} + a f\right )} \sqrt {-\frac {{\left (2 \, A^{2} + 20 i \, A B - 50 \, B^{2}\right )} c^{3}}{a^{2} f^{2}}} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-i \, f x - i \, e\right )}}{a f}\right ) + \sqrt {2} {\left ({\left (2 i \, A - 10 \, B\right )} c e^{\left (2 i \, f x + 2 i \, e\right )} + {\left (2 i \, A - 2 \, B\right )} c\right )} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{4 \, a f} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (B \tan \left (f x + e\right ) + A\right )} {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {3}{2}}}{i \, a \tan \left (f x + e\right ) + a}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.55, size = 109, normalized size = 0.76 \[ \frac {2 i c \left (i B \sqrt {c -i c \tan \left (f x +e \right )}+c \left (\frac {\left (-\frac {A}{2}-\frac {i B}{2}\right ) \sqrt {c -i c \tan \left (f x +e \right )}}{-c -i c \tan \left (f x +e \right )}-\frac {\left (5 i B +A \right ) \sqrt {2}\, \arctanh \left (\frac {\sqrt {c -i c \tan \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right )}{4 \sqrt {c}}\right )\right )}{f a} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.76, size = 138, normalized size = 0.96 \[ \frac {i \, {\left (\frac {\sqrt {2} {\left (A + 5 i \, B\right )} c^{\frac {5}{2}} \log \left (-\frac {\sqrt {2} \sqrt {c} - \sqrt {-i \, c \tan \left (f x + e\right ) + c}}{\sqrt {2} \sqrt {c} + \sqrt {-i \, c \tan \left (f x + e\right ) + c}}\right )}{a} - \frac {4 \, \sqrt {-i \, c \tan \left (f x + e\right ) + c} {\left (A + i \, B\right )} c^{3}}{{\left (-i \, c \tan \left (f x + e\right ) + c\right )} a - 2 \, a c} + \frac {8 i \, \sqrt {-i \, c \tan \left (f x + e\right ) + c} B c^{2}}{a}\right )}}{4 \, c f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 9.77, size = 189, normalized size = 1.31 \[ \frac {B\,c^2\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}}{a\,f\,\left (c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )-2\,a\,c\,f}-\frac {2\,B\,c\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}}{a\,f}+\frac {\sqrt {2}\,A\,{\left (-c\right )}^{3/2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}}{2\,\sqrt {-c}}\right )\,1{}\mathrm {i}}{2\,a\,f}+\frac {5\,\sqrt {2}\,B\,c^{3/2}\,\mathrm {atanh}\left (\frac {\sqrt {2}\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}}{2\,\sqrt {c}}\right )}{2\,a\,f}+\frac {A\,c^2\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}\,1{}\mathrm {i}}{a\,f\,\left (c+c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ - \frac {i \left (\int \frac {A c \sqrt {- i c \tan {\left (e + f x \right )} + c}}{\tan {\left (e + f x \right )} - i}\, dx + \int \frac {B c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )}}{\tan {\left (e + f x \right )} - i}\, dx + \int \left (- \frac {i A c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )}}{\tan {\left (e + f x \right )} - i}\right )\, dx + \int \left (- \frac {i B c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan ^{2}{\left (e + f x \right )}}{\tan {\left (e + f x \right )} - i}\right )\, dx\right )}{a} \]
Verification of antiderivative is not currently implemented for this CAS.
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